Physicshard · Past Paper
A stone is dropped from the top of a tower of height h. After 1s another stone is dropped from 20m below the top. Both reach bottom together. Height h is (g=10):
A25 m
B31.25 m
C45 m
D35 m
✓ Correct Answer: B — 31.25 m
Equating arrival times: sqrt(2h/g) = 1 + sqrt(2(h-20)/g). Solving gives h = 31.25m.
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