Physicsmedium · Past Paper
The critical angle for a medium is 45 degrees. What is its refractive index?
A1.414
B1.5
C2.0
D0.707
✓ Correct Answer: A — 1.414
n = 1/sin(C) = 1/sin(45) = 1/(1/sqrt(2)) = sqrt(2) ≈ 1.414.
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✓ Correct Answer: A — 1.414
n = 1/sin(C) = 1/sin(45) = 1/(1/sqrt(2)) = sqrt(2) ≈ 1.414.
Share this question