Chemistryhard · Past Paper
The Kw (ionic product) of water at 25 degrees C is:
A10^-7
B10^-14
C10^7
D10^14
✓ Correct Answer: B — 10^-14
Kw = [H+][OH-] = 1.0 x 10^-14 at room temperature.
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✓ Correct Answer: B — 10^-14
Kw = [H+][OH-] = 1.0 x 10^-14 at room temperature.
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