Trigonometrymedium · Past Paper
From top of cliff 20 m high, angle of depression of a buoy is 30°. Distance of buoy?
A20√3 m
B20 m
C40 m
D10√3 m
✓ Correct Answer: A — 20√3 m
tan 30 = 20 / d. 1/√3 = 20 / d => d = 20√3 m.
Share this question
More from Trigonometry
- What is the value of cos 90°?
- If 5 tan θ = 4, then (5 sin θ - 3 cos θ) / (5 sin θ + 2 cos θ) is equal to:
- The value of cot(theta) * tan(theta) is:
- Simplify: (sin^4 A - cos^4 A + 1) cosec^2 A
- From a point on the ground, the angles of elevation of the bottom and top of a transmission tower fixed at the top of a 20 m high building are 45° and 60°. Find the tower height.