Geometrymedium · Past Paper
The point on the x-axis which is equidistant from (2, -5) and (-2, 9) is:
A(-7, 0)
B(0, 7)
C(7, 0)
D(-6, 0)
✓ Correct Answer: A — (-7, 0)
Let point be (x, 0). (x-2)^2 + (0+5)^2 = (x+2)^2 + (0-9)^2 => x^2-4x+4+25 = x^2+4x+4+81 => -8x = 56 => x = -7.
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