Geometrymedium · Past Paper
The perpendicular distance from (1, 1) to the line 3x + 4y - 12 = 0 is:
A1
B5
C1.4
D7/5
✓ Correct Answer: A — 1
d = |3(1)+4(1)-12| / sqrt(3^2+4^2) = |3+4-12|/5 = |-5|/5 = 1.
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