Geometrymedium · Past Paper
The equation of a circle whose endpoints of a diameter are (x1, y1) and (x2, y2) is:
A(x-x1)(x-x2) + (y-y1)(y-y2) = 0
B(x-x1)^2 + (y-y1)^2 = r^2
Cx^2 + y^2 = r^2
D(x+x1)(x+x2) + (y+y1)(y+y2) = 0
✓ Correct Answer: A — (x-x1)(x-x2) + (y-y1)(y-y2) = 0
This is the diameter form of the circle equation.
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