Geometryeasy · Past Paper
The area of a triangle with vertices (a, 0), (0, b), and (0, 0) is:
Aab
B1/2 ab
C1/2 (a+b)
Dsqrt(a^2+b^2)
✓ Correct Answer: B — 1/2 ab
It is a right-angled triangle with base 'a' and height 'b'. Area = 1/2 * a * b.
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