Geometrymedium · Past Paper
Find the equation of a circle with center (2, -3) and radius 5.
Ax^2 + y^2 - 4x + 6y - 12 = 0
Bx^2 + y^2 + 4x - 6y - 12 = 0
Cx^2 + y^2 - 4x + 6y + 12 = 0
Dx^2 + y^2 - 2x + 3y - 25 = 0
✓ Correct Answer: A — x^2 + y^2 - 4x + 6y - 12 = 0
(x-2)^2 + (y+3)^2 = 25 => x^2-4x+4 + y^2+6y+9 = 25 => x^2+y^2-4x+6y-12=0.
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