Algebrahard · Past Paper
Solve for x and y: 2/(3x+2y) + 3/(3x-2y) = 17/5 and 5/(3x+2y) + 1/(3x-2y) = 2.
Ax=1, y=1/2
Bx=1/2, y=1
Cx=1, y=1
Dx=2, y=1
✓ Correct Answer: A — x=1, y=1/2
Let u=1/(3x+2y), v=1/(3x-2y). 2u+3v=17/5, 5u+v=2. Solving gives u=1/5, v=1. 3x+2y=5, 3x-2y=1. Adding: 6x=6 -> x=1. Subtracting: 4y=4 -> y=1.
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